We can notice a 45-voter coalition of voters backing the candidates A through J. Running D’Hondt versus the largest other coalitions, the 8 K and 7 L voters, this 45-voter coalition takes all 5 seats. So we can then eliminate all candidates not in the coalition, and then by recomputing the Droop quota to factor for the 15 now exhausted K and L ballots, just elect each of the 5 1st choice candidates in the coalition.
Here’s how this concept leads to the Condorcet winner in the single-winner case:
We can see an anti-M coalition of 58 voters, a majority, so eliminate M from contention (this requires Independence of Smith-dominated Alternatives). Now, the 42 M-top voters’ new 1st choice is N; this gives N 68 1st choice votes, a majority, so N wins (This is the Wikipedia example with Nashville as the CW).
I think this could lead to a simpler way of conceptualizing Condorcet PR; figure out how many seats each coalition is entitled to, then run a sequential PR method eliminating all non-guaranteed candidates at each stage.